Conditional and control flow

1. 조건문 연습, 그 return 값

# Assign True or False as appropriate on the lines below!

# 17 < 118 % 100

bool_one = (17 < 328)

# 100 == 33 * 3 + 1

bool_two = ( 100 == (2*50) )

# 19 <= 2**4

bool_three = (19 <= 19)

# -22 >= -18

bool_four = (-22 >= -18)

# 99 != 98 + 1

bool_five = ( 99 != (98 + 1) )

# 20 + -10 * 2 > 10 % 3 % 2

bool_one = (20 - 10) > 15

# (10 + 17)**2 == 3**6

bool_two = (10 + 17) == 3**16

# 1**2**3 <= -(-(-1))

bool_three = 1**2 <= -1

# 40 / 20 * 4 >= -4**2

bool_four = 40 * 4 >= -4

# 100**0.5 != 6 + 4

bool_five = 100 != 10**2

#대입 연산자 우선순위는 python에서도 많이 낮은 듯 하다.

2. boolean 연산

"""

     Boolean Operators

---------------------------

True and True is True

True and False is False

False and True is False

False and False is False

True or True is True

True or False is True

False or True is True

False or False is False

Not True is False

Not False is True

"""

bool_one = False and False

# -(-(-(-2))) == -2 and 4 >= 16**0.5

bool_two = -(-(-(-2))) == -2 and 4 >= 16**0.5

# 19 % 4 != 300 / 10 / 10 and False

bool_three = 19 % 4 != 300 / 10 / 10 and False

# -(1**2) < 2**0 and 10 % 10 <= 20 - 10 * 2

bool_four =  -(1**2) < 2**0 and 10 % 10 <= 20 - 10 * 2

# True and True

bool_five = True and True

# 2**3 == 108 % 100 or 'Cleese' == 'King Arthur'

bool_one = 2**3 == 108 % 100 or 'Cleese' == 'King Arthur'

# True or False

bool_two = True or False

# 100**0.5 >= 50 or False

bool_three = 100**0.5 >= 50 or False

# True or True

bool_four = True or True

# 1**100 == 100**1 or 3 * 2 * 1 != 3 + 2 + 1

bool_five = 1**100 == 100**1 or 3 * 2 * 1 != 3 + 2 + 1

# not True

bool_one = not True

# not 3**4 < 4**3

bool_two = not 3**4 < 4**3

# not 10 % 3 <= 10 % 2

bool_three = not 10 % 3 <= 10 % 2

# not 3**2 + 4**2 != 5**2

bool_four = not 3**2 + 4**2 != 5**2

# not not False

bool_five = not not False

# False or not True and True

bool_one = False or not True and True

# False and not True or True

bool_two = False and not True or True

# True and not (False or False)

bool_three = True and not (False or False)

# not not True or False and not True

bool_four = not not True or False and not True

# False or not (True and True)

bool_five = False or not (True and True)

3. if-else

response = 'Y'

answer = "Left"

if answer == "Left":

    print "This is the Verbal Abuse Room, you heap of parrot droppings!"

    

# Will the above print statement print to the console?

# Set response to 'Y' if you think so, and 'N' if you think not.

4.

def using_control_once():

    if True:

        return "Success #1"

def using_control_again():

    if 1>0:

        return "Success #2"

print using_control_once()

print using_control_again()

5. 

answer = "'Tis but a scratch!"

def black_knight():

    if answer == "'Tis but a scratch!":

        return True

    else:             

        return False       # Make sure this returns False

def french_soldier():

    if answer == "Go away, or I shall taunt you a second time!":

        return True

    else:             

        return   False     # Make sure this returns False

6. if elif else (c언어 case 구문처럼 콜론으로 )

def greater_less_equal_5(answer):

    if answer > 5:

        return 1

    elif answer <5:          

        return -1

    else:

        return 0

        

print greater_less_equal_5(4)

print greater_less_equal_5(5)

print greater_less_equal_5(6)

7. 

def the_flying_circus():

    if True or True:    # Start coding here!

        # Don't forget to indent

        # the code inside this block!

        return True

    elif 1<0:

        # Keep going here.

        # You'll want to add the else statement, too!

        return True

    else :

        return True